Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 499: 39

Answer

$\displaystyle \frac{7}{9}$

Work Step by Step

Dividing with $\displaystyle \frac{P}{Q}$ equals multiplying with the reciprocal, $\displaystyle \frac{Q}{P}.$ $\displaystyle \frac{x+1}{3}\div\frac{3x+3}{7}=\frac{x+1}{3}\cdot\frac{7}{3x+3}\qquad$... factor what you can $=\displaystyle \frac{x+1}{3}\cdot\frac{7}{3(x+1)}\qquad$... divide out the common factors $=\displaystyle \frac{1}{3}\cdot\frac{7}{3(1)}\qquad$ = $\displaystyle \frac{7}{9}$
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