Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 436: 6

Answer

$(x+1)(x+12)$

Work Step by Step

The given expression, $ x^2+13x+12 ,$ has $c= 12 $ and $b= 13 .$ The possible factors of $c$ are $ \{ 1,12 \} ,\{ 2,6 \} ,\{ 3,4 \} ,\{ -1,-12 \} ,\{ -2,-6 \} ,\{ -3,-4 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ 1,12 \}.$ Hence, the factored form is \begin{array}{l}\require{cancel} (x+1)(x+12) .\end{array}
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