Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 436: 47

Answer

$10(x+6)(x-10)$

Work Step by Step

Factoring the $GCF= 10 ,$ the given expression, $ 10x^2-40x-600 ,$ is equivalent to \begin{array}{l}\require{cancel} 10(x^2-4x-60) .\end{array} The trinomial expression above has $c= -60 $ and $b= -4 .$ The possible factors of $c$ are $ \{ 1,-60 \} ,\{ 2,-30 \} ,\{ 3,-20 \} ,\{ 4,-15 \} ,\{ 5,-12 \} ,\{ 6,-10 \} ,\{ -1,60 \} ,\{ -2,30 \} ,\{ -3,20 \} ,\{ -4,15 \} ,\{ -5,12 \} ,\{ -6,10 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ 6,-10 \}.$ Hence, the factored form of the given expression is \begin{array}{l}\require{cancel} 10(x+6)(x-10) .\end{array}
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