Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Review Exercises - Page 479: 50

Answer

$(2y+1)(5y+2)$

Work Step by Step

$10y^{2}+9y+2$ ... Searching for two factors of $ac=20$ whose sum is $b=9,$ we find$\qquad 5$ and $4.$ Rewrite the middle term and factor in pairs: $=10y^{2}+5y+4y+2=$ $=5y(2y+1)+2(2y+1)]$ =$(2y+1)(5y+2)$
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