Answer
$(x-3)(x^{2}+3x+9)$
Work Step by Step
$ x^{3}-27\qquad$...use the difference of two cubes:
$\mathrm{A}^{3}-\mathrm{B}^{3} = (\mathrm{A}-\mathrm{B})(\mathrm{A}^{2} + \mathrm{A}\mathrm{B} + B^{2})$
$=(x)^{3}-3^{3}$
$=(x-3)(x^{2}+3x+9)$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Review Exercises - Page 479: 42
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