Answer
$(x-3y)(2x-y)$
Work Step by Step
$2x^{2}-7xy+3y^{2}$
... Searching for two factors of $ac=6$ whose sum is $b=-7,$
we find$\qquad-6$ and $-1.$
Rewrite the middle term and factor in pairs:
$=2x^{2}-6xy-xy+3y^{2}=$
$=2x(x-3y)-y(x-3y)$
=$(x-3y)(2x-y)$
