Answer
$x(x+8)(2x-9)$
Work Step by Step
$ 2x^{3}+7x^{2}-72x\qquad$...factor out the common term, $x$.
$=x(2x^{2}+7x-72)$
... Searching for two factors of $ac=-144$ whose sum is $b=7,$
we find$\qquad 16$ and $-9.$
Rewrite the middle term and factor in pairs:
$=x(2x^{2}+16x-9x-72)=$
$=x[2x(x+8)-9(x+8)]$
=$x(x+8)(2x-9)$
