Answer
-$\frac{64}{27a^9}$
Work Step by Step
$(\frac{-4}{3a^3})^3$=$\frac{(-4)^3}{3^3a^9}$=-$\frac{64}{27a^9}$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 5 - Section 5.5 - Dividing Polynomials - Exercise Set - Page 386: 31
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