Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.5 - Dividing Polynomials - Exercise Set: 31

Answer

-$\frac{64}{27a^9}$

Work Step by Step

$(\frac{-4}{3a^3})^3$=$\frac{(-4)^3}{3^3a^9}$=-$\frac{64}{27a^9}$
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