Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.5 - Dividing Polynomials - Exercise Set - Page 386: 27

Answer

$\dfrac{x^6}{64}$

Work Step by Step

RECALL: (i) $\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}, b\ne0$ (ii) $(a^m)^n=a^{mn}$ Use rule (i) above to obtain: $=\dfrac{(x^2)^3}{4^3} \\=\dfrac{(x^2)^3}{4(4)(4)} \\=\dfrac{(x^2)^3}{64}$ Use rule (ii) above to obtain: $=\dfrac{x^{2(3)}}{64} \\=\dfrac{x^6}{64}$
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