Answer
$2x^2y+13xy+13$
Work Step by Step
Removing the grouping symbols and then combining like terms, the given expression, $
(4x^2y+8xy+11)+(-2x^2y+5xy+2)
,$ simplifies to
\begin{array}{l}\require{cancel}
4x^2y+8xy+11-2x^2y+5xy+2
\\\\=
(4x^2y-2x^2y)+(8xy+5xy)+(11+2)
\\\\=
2x^2y+13xy+13
.\end{array}