Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 8

Answer

$5y^2-6y-8$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (5y+4)(y-2) ,$ is \begin{array}{l}\require{cancel} 5y(y)+5y(-2)+4(y)+4(-2) \\\\= 5y^2-10y+4y-8 \\\\= 5y^2-6y-8 .\end{array}
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