Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 6

Answer

$3x^2+16x-35$

Work Step by Step

Using $(a+b)(c+d)=ab+ad+bc+bd$ or the FOIL Method, the product of the given expression, $ (3x-5)(x+7) ,$ is \begin{array}{l}\require{cancel} 3x(x)+3x(7)-5(x)-5(7) \\\\= 3x^2+21x-5x-35 \\\\= 3x^2+16x-35 .\end{array}
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