Answer
x$^3$+27y$^3$
Work Step by Step
(x+3y)(x$^2$-3xy+9y$^2$)
This problem is a special product where the multiplication results in the sum of the cubes of the two terms in the first set of parentheses.
((x)$^3$+(3y)$^3$)
(x$^3$+27y$^3$)
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