Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 9

{(4,5)}

2x-y=3 3=2x-y 3+y=2x y=2x-3 Plug this value for y into the other equation. 5x-2y=10 5x-2(2x-3)=10 5x-2(2x)-2(-3)=10 5x-4x+6=10 x+6=10 x=10-6 x=4 Plug this back into the first equation to find y. y=2x-3 y=2(4)-3 y=8-3 y=5 Therefore the solution is {(4,5)}