Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 7

{(-1,3)}

x+5y=14 x=14-5y Plug this value for x into the other equation. 2x-y=-5 2(14-5y)-y=-5 2(14)-2(5y)-y=-5 28-10y-y=-5 28-11y=-5 -11y=-5-28 -11y=-33 y=$\frac{-33}{-11}$ y=3 Plug this back into the first equation. x=14-5y x=14-5(3) x=14-15 x=-1 Therefore, the solution is {(-1,3)}