Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by the Substitution Method - Exercise Set - Page 300: 17

{(0,0)}

x-3y=0 x=0+3y x=3y Plug this value for x into the other equation. 5x+2y=0 5(3y)+2y=0 15y+2y=0 17y=0 y=$\frac{0}{17}$ y=0 Plug this back into the first equation to find x. x=3y x=3(0) x=0 Therefore the solution is {(0,0)}