Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 3 - Section 3.3 - Slope - Exercise Set - Page 242: 39

Answer

Opposite sides of the four sided figure lie on parallel lines, with one pair having slopes $-\displaystyle \frac{2}{5}$ and the other with $\displaystyle \frac{4}{3}.$

Work Step by Step

Use: $m=\displaystyle \frac{\text{change in y}}{\text{change in x}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$, parallel lines have equal slopes. Plot the points (see below). The slope of the line passing through $(0,1)$ and $(5,-1)$ is $m=\displaystyle \frac{-1-1}{5-0}=\frac{-2}{5}$ The slope of the line passing through $(-3,-3)$ and $(2,-5)$ is $m=\displaystyle \frac{-5-(-3)}{2-(-3)}=\frac{-2}{5}$ So, we have a pair of parallel lines. The slope of the line passing through $(0,1)$ and $(-3,-3)$ is $m=\displaystyle \frac{-3-1}{-3-0}=\frac{-4}{-3}=\frac{4}{3}$ The slope of the line passing through $(2,-5)$ and $(5,-1)$ is $m=\displaystyle \frac{-1-(-5)}{5-2}=\frac{4}{3}$, ... and we have another pair of parallel lines. Opposite sides of the four sided figure lie on parallel lines, with one pair having slopes $-\displaystyle \frac{2}{5}$ and the other with $\displaystyle \frac{4}{3}.$
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