Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Review Exercises - Page 204: 56

Answer

135 yd$^2$

Work Step by Step

A=$\frac{1}{2}$h(b$_1$+b$_2$) A=$\frac{1}{2}$(10)(5+22) A=$\frac{1}{2}$(10)(27) A=$\frac{1}{2}$(270) A=135 yd$^2$
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