Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Section 1.2 - Fractions in Algebra - Exercise Set: 123

Answer

C=20$^\circ$

Work Step by Step

C=$\frac{5}{9}$(F-32) C=$\frac{5}{9}$(68-32) C=$\frac{5}{9}$(36) C=$\frac{5\times36}{9}=\frac{180}{9}=\frac{180\div9}{9\div9}$ C=20
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