Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 1 - Review Exercises: 98

Answer

-$\frac{2}{5}$

Work Step by Step

$\frac{1}{2}$-$\frac{2}{3}$$\div$$\frac{5}{9}$+$\frac{3}{10}$ First change the division to multiplication of the reciprocal of the divisor $\frac{1}{2}$-$\frac{2}{3}$$\times$$\frac{9}{5}$+$\frac{3}{10}$ Then multiply $\frac{1}{2}$-$\frac{18}{15}$+$\frac{3}{10}$ Then reduce that product by 3 $\frac{1}{2}$-$\frac{6}{5}$+$\frac{3}{10}$ Then make all of the fractions have a common denominator of 10. $\frac{1(5)}{2(5)}$-$\frac{6(2)}{5(2)}$+$\frac{3}{10}$ $\frac{5}{10}$-$\frac{12}{10}$+$\frac{3}{10}$ Then subtract -$\frac{7}{10}$+$\frac{3}{10}$ Then add -$\frac{4}{10}$ Then reduce by 2. -$\frac{2}{5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.