Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Appendix - Mean, Median, and Mode - Exercise Set: 25

Answer

mean is 45.2 median is 46 mode 46 and 47

Work Step by Step

To find the mean, sum all the ages and divide the sum by the number of ages given. $mean=\frac{42+43+46+46+47+47}{6}=\frac{271}{6}=45.2$ To find the median, list the ages in order and find the age that appears at the midpoint of the list. If the number of ages given is even, find the mean of the two ages at the midpoint of the list. $42, 43, \underset\uparrow46, \underset\uparrow46, 47, 47$ $median=\frac{46+46}{2}=\frac{92}{2}=46$ To find the mode, identify the age that appears most often in the list. If more than one value appears most often, all are the mode. 46 and 47 are the only ages repeated and each is repeated twice, so both are the mode.
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