Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 726: 8

Answer

$x=\frac{4}{3}$

Work Step by Step

Note that $125=5^3$. Write $125$ as $5^3$ to obtain: $5^{3x-1}=5^3$ RECALL: If $a^x = a^y$, then $x=y$. Use the rule above to obtain: $5^{3x-1}=5^3 \\3x-1=3 \\3x=3+1 \\3x=4 \\x=\frac{4}{3}$
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