Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 726: 22

Answer

$x \approx 0.91$

Work Step by Step

RECALL: $\log{10^x}=x$ Take the common logarithm of both sides to obtain: $\log{10^x}=\log{8.07}$ Use the rule above to obtain: $x=\log{8.07}$ Use a scientific calculator to obtain: $x=0.9068735347 \\x \approx 0.91$
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