Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 726: 11

Answer

$x=\frac{3}{2}$

Work Step by Step

Note that: $9=3^2$ AND $27=3^3$ Write each side with a base of $3$ to obtain: $(3^2)^{x}=3^3 \\3^{2x}=3^3$ RECALL: If $a^x = a^y$, then $x=y$. Use the rule above to obtain: $3^{2x}=3^3 \\2x=3 \\x=\frac{3}{2}$
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