Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Concept and Vocabulary Check - Page 569: 6

Answer

First :- $18$ Second :- $-15i$ Third :- $12i$ Fourth :- $-10i^2$ Fifth :- $10$

Work Step by Step

The given expression is $=(3+2i)(6-5i)$ Use the FOIL method. The product of the first terms: $=(3)\cdot (6)=18$. The product of the outside terms: $=(3)\cdot (-5i)=-15i$. The product of the inside terms: $=(2i)\cdot (6)=12i$. The product of the last terms: $=(2i)\cdot (-5i)=-10i^2=10$.
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