Answer
$5.4$ feet.
Work Step by Step
The given equation is
$\Rightarrow t=\frac{\sqrt d}{2}$
The hang time was $t=1.16$.
Substitute the value of $t$ into the equation.
$\Rightarrow 1.16=\frac{\sqrt d}{2}$
Multiply both sides by $2$.
$\Rightarrow 2\times 1.16=2\times\frac{\sqrt d}{2}$
Simplify.
$\Rightarrow 2.32=\sqrt d$
Square both sides.
$\Rightarrow (2.32)^2=(\sqrt d)^2$
Simplify.
$\Rightarrow 5.3834=d$
Hence, the approximate vertical distance is $5.4$ feet.
