Answer
no solution
Work Step by Step
Subtract 8 on both sides to obtain:
$(x-3)^{\frac{1}{2}}=-2$
RECALL:
(1) $a^{\frac{1}{2}}=\sqrt{a}$
(2) For any real number $a$, $\sqrt{a} \ge 0$
Use rule (1) above to obtain:
$\sqrt{x-3} = -2$
According to rule (2) above, the principal square root of any real number cannot be negative.
with a negative number on the right side of the equation, the given equation has no solution.
