Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 560: 27

Answer

$x = \frac{5}{2}$

Work Step by Step

Subtract 4 on both sides to obtain: $(2x+3)^{\frac{1}{3}}=2$ Cube both sides to obtain: $\left((2x+3)^{\frac{1}{3}}\right)^3=2^3 \\(2x+3)^{\frac{1}{3}(3)}=8 \\(2x+3)^1=8 \\2x+3=8$ Subtract 3 on both sides to obtain: $2x=5$ Divide 2 on both sides to obtain: $x = \frac{5}{2}$
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