Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 539: 71

Answer

$25x\sqrt {2x}$.

Work Step by Step

The given expression is $=5\sqrt {2x^3}+\frac{30x^3\sqrt {24x^2}}{3x^2\sqrt {3x}}$ Factor the radicands into square terms. $=5\sqrt {2x^2\cdot x}+\frac{3\cdot 10x^2\cdot x\sqrt {2^2\cdot 3\cdot 2x^2}}{3x^2\sqrt {3x}}$ Simplify. $=5\cdot x\sqrt {2x}+\frac{3x^2\cdot 10x\cdot 2x\sqrt { 3}\cdot \sqrt{2}}{3x^2\sqrt {3x}}$ Cancel out similar terms in the fraction. $=5x\sqrt {2x}+20x\sqrt {2x}$ By using the distributive property: $=(5+20)x\sqrt {2x}$ Simplify. $=25x\sqrt {2x}$.
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