Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 539: 68

Answer

$ \frac{31\sqrt {3}}{14} $.

Work Step by Step

The given expression is $=\frac{\sqrt {27}}{2}+\frac{\sqrt {75}}{7}$ Factor the radicands into square terms. $=\frac{\sqrt {3^2\cdot 3}}{2}+\frac{\sqrt {5^2\cdot 3}}{7}$ Simplify. $=\frac{3\sqrt {3}}{2}+\frac{5\sqrt { 3}}{7}$ By using the distributive property: $=\sqrt {3} \left ( \frac{3}{2}+\frac{5}{7} \right )$ Multiply and divide the first fraction by $7$ and the second by $2$ $=\sqrt {3} \left ( \frac{7\cdot 3}{7\cdot 2}+\frac{2\cdot 5}{2\cdot 7} \right )$ $=\sqrt {3} \left ( \frac{21}{14}+\frac{10}{14} \right )$ $=\sqrt {3} \left ( \frac{21+10}{14} \right )$ Simplify. $=\sqrt {3} \left ( \frac{31}{14} \right )$ Clear the parentheses. $= \frac{31\sqrt {3}}{14} $.
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