Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 539: 65

Answer

$\sqrt[3] {a^2-ab+b^2}$.

Work Step by Step

The given expression is $\frac{\sqrt[3] {a^3+b^3}}{\sqrt[3] {a+b}}$ Use the quotient rule $\frac{\sqrt[n] a}{\sqrt[n] b} = \sqrt[n] {\frac{a}{b}}$. $=\sqrt[3] {\frac{a^3+b^3}{a+b}}$ Factor the numerator using the formula $a^3+b^3=(a+b)(a^2-ab+b^2)$. $=\sqrt[3] {\frac{(a+b)(a^2-ab+b^2)}{a+b}}$ Cancel out common terms. $=\sqrt[3] {a^2-ab+b^2}$.
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