Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set: 14

Answer

$15\sqrt{3}$

Work Step by Step

Simplify each radical to obtain: $=5\sqrt{4(3)} +\sqrt{25(3)} \\=5\sqrt{2^2(3)} +\sqrt{5^2(3)} \\=5(2)\sqrt{3}+5\sqrt{3} \\=10\sqrt{3} + 5\sqrt{3}$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac-bc=(a-b)c$ Use rule (1) above to combine like terms and obtain: $=(10+5)\sqrt{3} \\=15\sqrt{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.