Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 15

Answer

$\sqrt{x}$

Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $\require{cancel} \\=\sqrt{\dfrac{2x}{3} \cdot \dfrac{3}{2}} \\=\sqrt{\dfrac{\cancel{2}x}{\cancel{3}} \cdot \dfrac{\cancel{3}}{\cancel{2}}} \\=\sqrt{x}$
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