Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 13

Answer

$\sqrt[6]{(x-4)^5}$

Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Also, $(x-c)^{a}+(x-c)^{b}=(x-c)^{ab}$ Use the rules above to obtain: $=\sqrt[6]{(x-4)(x-4)^4} \\=\sqrt[6]{(x-4)^{1+4}} \\=\sqrt[6]{(x-4)^5}$
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