Answer
$h(5)=3$
$h(3)=1$
$h(0)=2$
$h(-5)=7$.
Work Step by Step
The given function is
$h(x)=\sqrt{(x-2)^2}$
Plug $x=5$ into the function.
$h(5)=\sqrt{(5-2)^2}$
Simplify.
$h(5)=\sqrt{(3)^2}$
$h(5)=\sqrt{3^2}$
$h(5)=3$
Plug $x=3$ into the function.
$h(3)=\sqrt{(3-2)^2}$
Simplify.
$h(3)=\sqrt{(1)^2}$
$h(3)=\sqrt{1^2}$
$h(3)=1$
Plug $x=0$ into the function.
$h(0)=\sqrt{(0-2)^2}$
Simplify.
$h(0)=\sqrt{(-2)^2}$
$h(0)=\sqrt{2^2}$
$h(0)=2$
Plug $x=-5$ into the function.
$h(-5)=\sqrt{(-5-2)^2}$
Simplify.
$h(-5)=\sqrt{(-7)^2}$
$h(-5)=\sqrt{7^2}$
$h(-5)=7$.
