Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 511: 16

Answer

$13$

Work Step by Step

Simplify the expression inside the radical sign to obtain: $=\sqrt{169}$ Recall, square roots cancel out exponents of two. Thus, we obtain: $=\sqrt{13^2} \\=13$
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