Answer
$(-\infty, +\infty)$
Work Step by Step
For any real number $x$, $\sqrt[3]{x}$ exists (or is defined).
Thus, the domain of $f(x)=\sqrt[3]{x}$ is the set of all real numbers.
In interval notation, the domain is $(-\infty, +\infty)$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.1 - Radical Expressions and Functions - Concept and Vocabulary Check - Page 511: 9
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