Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Concept and Vocabulary Check - Page 371: 15

Answer

True.

Work Step by Step

The statement is true because $x^6=(x^2)^3$ and $1000y^3=(10y)^3$.
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