Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 82

Answer

$4xy^5(x+8)(x-2)$.

Work Step by Step

The given expression is $=4x^3y^5+24x^2y^5-64xy^5$ Factor out $4xy^5$. $=4xy^5(x^2+6x-16)$ Rewrite $6x$ as $8x-2x$. $=4xy^5(x^2+8x-2x-16)$ Group terms. $=4xy^5[(x^2+8x)+(-2x-16)]$ Factor from each group. $=4xy^5[x(x+8)-2(x+8)]$ Factor out $(x+8)$. $=4xy^5(x+8)(x-2)$.
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