Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 68

Answer

$(5a+3b)(3a-2b)$

Work Step by Step

$15a^{2}-ab-6b^{2}$ ... Searching for two factors of $ac=-90$ whose sum is $b=-1,$ we find$\qquad 9$ and $-10.$ Rewrite the middle term and factor in pairs: $=15a^{2}+9ab-10ab-6b^{2}=$ $=3a(5a+3b)-2b(5a+3b)$ = $(5a+3b)(3a-2b)$
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