Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 57

Answer

$(y-3)(6y-5)$

Work Step by Step

$6y^{2}-23y+15=$ ... ... Searching for two factors of $ac=+90$ whose sum is $b=-23,$ we find$\qquad-18$ and $-5.$ Rewrite the middle term and factor in pairs: $=6y^{2}-18y-5y+15=$ $=6y(y-3)-5(y-3)$ = $(y-3)(6y-5)$
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