Answer
$(2x-3)(4x-3)$
Work Step by Step
$8x^{2}-18x+9=$
... ... Searching for two factors of $ac=+72$ whose sum is $b=-18,$
we find$\qquad-6$ and $-12.$
Rewrite the middle term and factor in pairs:
$=8x^{2}-12x-6x+9=$
$=4x(2x-3)-3(2x-3)$
= $(2x-3)(4x-3)$
