Answer
$(2x+3)(5x+2)$
Work Step by Step
$10x^{2}+19x+6=$
... ... Searching for two factors of $ac=+60$ whose sum is $b=+19,$
we find$\qquad+15$ and $+4.$
Rewrite the middle term and factor in pairs:
$=10x^{2}+15x+4x+6=$
$=5x(2x+3)+2(2x+3)$
= $(2x+3)(5x+2)$