Answer
$(y+8)(3y-2)$
Work Step by Step
$3y^{2}+22y-16=$
... ... Searching for two factors of $ac=-48$ whose sum is $b=+22,$
we find$\qquad+24$ and $-2.$
Rewrite the middle term and factor in pairs:
$=3y^{2}+24y-2y-16=$
$=3y(y+8)-2(y+8)$
= $(y+8)(3y-2)$
