Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 45

Answer

$(x+1)(3x+5)$

Work Step by Step

$3x^{2}+8x+5=$ ... ... Searching for two factors of $ac=15$ whose sum is $b=+8,$ we find$\qquad+5$ and $+3.$ Rewrite the middle term and factor in pairs: =$3x^{2}+3x+5x+5=$ $=3x(x+1)+5(x+1)$ = $(x+1)(3x+5)$
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