Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 361: 42

Answer

$(x^{2}-5)(x^{2}+1)$

Work Step by Step

Substituting $x^{2}=t$, the trinomial becomes quadratic, $t^{3}-4t-5=$ ... Searching for two factors of $-5$ whose sum is $-4,$ we find$\qquad-5$ and $+1$ $=(t-5)(t+1)$ ... bring back x = $(x^{2}-5)(x^{2}+1)$
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