Answer
$(x^{3}+3)(x^{3}-2)$
Work Step by Step
Substituting $x^{3}=t$, the trinomial becomes quadratic,
$t^{3}+t-6=$
... Searching for two factors of $-6$ whose sum is $+1,$
we find$\qquad+3$ and $-2$
$=(t+3)(t-2)$
... bring back x
= $(x^{3}+3)(x^{3}-2)$
