Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set: 36

Answer

$4y(y+6)(y-3)$

Work Step by Step

All terms are divisible by $4y$, so factor out $4y$ to obtain: $=4y(y^2+3y-18)$ Factor the trinomial. Look for factors of $-18$ whose sum is $3$. These factors are $6$ and $-3$. This means that the trinomial can be factored as $(y+6)(y-3)$. Thus, the completely factored form of the given polynomial is: $=4y(y+6)(y-3)$
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