Answer
$3y(y-3)(y-2)$
Work Step by Step
All terms are divisible by $3y$, so factor out $3y$ to obtain:
$=3y(y^2-5y+6)$
Factor the trinomial. Look for factors of $6$ whose sum is $-5$. These factors are $-3$ and $-2$.
This means that the trinomial can be factored as $(y-3)(y-2)$.
Thus, the completely factored form of the given polynomial is:
$=3y(y-3)(y-2)$
