Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.4 - Linear Functions and Slope - Exercise Set - Page 152: 27

Answer

$\begin{array}{ll} line & slope\\ L_{1} & 2/3\\ L_{2} & -2\\ L_{3} & -1/2 \end{array}$

Work Step by Step

Slope is defined as $m=\displaystyle \frac{\text{change in y}}{\text{change in x}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} .$ --- Line $L_{1}$ passes through $(-3,0)$ and $(0,2)$ $m_{1}=\displaystyle \frac{2-0}{0-(-3)}=\frac{2}{3}$ Line $L_{1}$ passes through $(0,4)$ and $(2,0)$ $m_{1}=\displaystyle \frac{0-4}{2-0}=\frac{-4}{2}=-2$ Line $L_{1}$ passes through $(0,-3)$ and $(2,-4)$ $m_{1}=\displaystyle \frac{-4-(-3)}{2-0}=\frac{-1}{2}$
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